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61. A person walks 250 ft north and turns west. Walking at the rate of 4.0 ft/s, at what rate is the distance between the person and the starting point increasing 1.0 min after turning west? 62. A glass prism for refracting light has equilateral triangular and a volume of 45 cm³ Find 74. A spe edges what 

          61. A person walks 250 ft north and turns west. Walking at the rate of 4.0 ft/s, at what rate is the distance between the person and the starting point increasing 1.0 min after turning west?
62. A glass prism for refracting light has equilateral triangular and a volume of 45 cm³ Find
74. A spe edges what
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61. A person walks 250 ft north and turns west. Walking at the rate of 4.0 ft/s, at what rate is the distance between the person and the starting point increasing 1.0 min after turning west? 62. A glass prism for refracting light has equilateral triangular and a volume of 45 cm³ Find 74. A spe edges what

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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61. A person walks 250 ft north and turns west. Walking at the rate of 4.0 ft/s, at what rate is the distance between the person and the starting point increasing 1.0 min after turning west? 61. A person walks 250 ft north and turns west.Walking at the rate of 4.0 ft/s,at what rate is the distance between the person and the starting point increasing 1.0 min after turning west? 62. A glass prism for refracting light has equilateral triangular 74.Aspe edges what
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Transcript

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00:01 It is given that the rate of walking away from lamp post of a person is 40 feet per minute.
00:06 When the person is 8 feet away from the lamp post, the shadow length is 10 feet.
00:10 And we have to find the rate of increase of shadow length when the person is 32 feet away from the lamp post.
00:16 Let us start with the solution.
00:18 Firstly, by similar triangle properties we have, let us suppose that length of the lamp post is equal to l.
00:40 Therefore, it would be equal to l divided by x plus y and it is equal to 5 divided by y.
00:47 From here we get l is equal to 5x plus 5y divided by y and it is given in the problem that when the person is 8 feet away that is x is equal to 8 feet then the shadow length that is y is equal to 10 feet...
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