A particle moves on a vertical line so that its coordinate at time t is y = t^3 - 12t + 3t^0. (1. Find the velocity function. (2. When is the particle at rest? 3. When is the particle moving in the positive direction? 4. Find the distance that the particle travels in the time interval 0 < t < 3. (5. When is the particle speeding up?
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To find the velocity function, we need to find the derivative of the position function with respect to time. The position function is y = t^3 - 12t + 3t^0. Taking the derivative, we get: dy/dt = 3t^2 - 12 + 0 dy/dt = 3t^2 - 12 So, the velocity function is Show more…
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