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6. Evaluate $\int_C (x + yz) ds$ where C is the line segment from (0, 0, 0) to (6, 2, 2)

          6. Evaluate $\int_C (x + yz) ds$ where C is the line segment from (0, 0, 0) to (6, 2, 2)
        
6. Evaluate (x + yz) ds where C is the line segment from (0, 0, 0) to (6, 2, 2)

Added by Donna C.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Evaluate ∫( + yz) ds where C is the line segment from (0, 0, 0) to (6, 2, 2).
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Transcript

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00:01 So evaluate this integral.
00:03 Well, we first parameterize the curve and this one is easy.
00:08 X is t, y is 2t, z is 3t, and t goes from 0 to 1.
00:17 So this way you parameterize, you get x is t, y is 2t, z is 3t, so 6t is square.
00:27 And ds is square root of 1 plus one square plus two square plus three square.
00:39 So it's square root of 14 d t...
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