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Use part one of the fundamental theorem of calculus to find the derivative of the function.
$f(x) = \int_{x}^{0} \sqrt{6 + \sec(3t)} dt$
[Hint: $\int_{x}^{0} \sqrt{6 + \sec(3t)} dt = - \int_{0}^{x} \sqrt{6 + \sec(3t)} dt$]
$f'(x) = |$
Check the plus and minus signs of all terms and/or values.
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Please try again. Recall the Fundamental Theorem of Calculus: If $f$ is differentiable on $[a, b]$, then
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