00:01
Hi, here.
00:03
In this question we are given an integral.
00:06
Integral is x plus 1 multiplied with e raise to x plus 1 whole square dx.
00:12
Now here we need to use the substitution method.
00:15
Therefore here we have u equals to x plus 1 whole square.
00:19
Now differentiating both the side we have du equals to 2 times x plus 1 d x.
00:25
Therefore here our integral can further reduce to 1 by 2 times of integer.
00:31
Integration 2 times x plus 1 e raised 2 x plus 1 square d x.
00:38
Now here substituting the above value, here we have 1 by 2 time e raised 2 u d u.
00:46
We know that integration of e raise to x is e rest to x therefore here in our case we have 1 by 2 e raised to u plus c.
00:53
Now substituting the value of e we got our required solution as the value of integral is 1 by 2 time e raised to x plus 1 whole square plus c.
01:06
Now here further we are given second integral which is 2x plus 2 raise to 3 dx.
01:13
Now here let u equals to 2x plus 2 as we need to use substitution method.
01:20
Therefore here further we can say that differentiating we have du equals to 2 times d x...