7. (10 pts) State why the integral is improper. Evaluate and state whether the integral converges or diverges. Hint: look for discontinuities of the function.\\ $\int_0^2 \frac{1}{\sqrt[3]{x-1}} dx$
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Step 1: The integral is improper because the integrand has a discontinuity at $x=1$, which is within the interval of integration. Show more…
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