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7. [-/14.32 Points] DETAILS MY NOTES SCALCET8 2.5.055. PRACTICE ANOTHER Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. $e^x = 4 - 3x$, $(0, 1)$ The equation $e^x = 4 - 3x$ is equivalent to the equation $f(x) = e^x - 4 + 3x = 0$. $f(x)$ is continuous on the interval $[0, 1]$, $f(0) = $ f(1) = . Since ---Select--- < 0 < ---Select---, there is a number c in (0, 1) such that $f(c) = 0$ by the Intermediate Value Theorem. Thus, there is a root of the equation $e^x = 4 - 3x$, in the interval $(0, 1)$. Submit Answer Home My Assignments Request Extension

          7. [-/14.32 Points] DETAILS
MY NOTES
SCALCET8 2.5.055.
PRACTICE ANOTHER
Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval.
$e^x = 4 - 3x$, $(0, 1)$
The equation $e^x = 4 - 3x$ is equivalent to the equation $f(x) = e^x - 4 + 3x = 0$. $f(x)$ is continuous on the interval $[0, 1]$, $f(0) = 
$
f(1) = 
. Since ---Select--- < 0 < ---Select---, there is a number c in (0, 1) such that $f(c) = 0$ by the Intermediate Value Theorem. Thus,
there is a root of the equation $e^x = 4 - 3x$, in the interval $(0, 1)$. 
Submit Answer
Home My Assignments
Request Extension

7. [-/14.32 Points] DETAILS
MY NOTES
SCALCET8 2.5.055.
PRACTICE ANOTHER
Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval.
e^x = 4 - 3x, (0, 1)
The equation e^x = 4 - 3x is equivalent to the equation f(x) = e^x - 4 + 3x = 0. f(x) is continuous on the interval [0, 1], f(0) =
f(1) =
. Since —Select— < 0 < —Select—, there is a number c in (0, 1) such that f(c) = 0 by the Intermediate Value Theorem. Thus,
there is a root of the equation e^x = 4 - 3x, in the interval (0, 1).
Submit Answer
Home My Assignments
Request Extension

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