7. Evaluate the limit.\\ $\lim_{t \to 0} -4e^t \cdot \frac{\sin(t)}{-3t} \cdot (t-1)^2$
Added by Tonya C.
Close
Step 1
lim < -4e', sin(t) / -3t . (t-1)^2> = lim < -4e', -sin(t) / 3t . (t-1)^2> t->0 t->0 Show more…
Show all steps
Your feedback will help us improve your experience
Adi S and 86 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Evaluate the limit. Note: two 'o's make infinity (oo). lim t->0 <-4e^t, sin(t)/t, (t+2)^2> #11 Points possible: 1. Total attempts: 0 Evaluate the limit. Note: two 'o's make infinity (oo). lim t->0 <5e^-t, e^-5t, ln(4-t)>
Adi S.
$8-68$ Find the limit. Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. If I'Hospital's Rule doesn't apply, explain why. $$\lim _{t \rightarrow 0} \frac{e^{2 t}-1}{\sin t}$$
Inverse Functions
Indeterminate Forms and l'Hopital's Rule
Evaluate lim_{x o 0} x^2 sin(1/x) A. 1 B. ∞ C. 0 D. π^2 E. does not exist
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD