So, $n_3$ divides 10 and $n_3 \equiv 1 \pmod{3}$. The possible values for $n_3$ are 1 and 10. Similarly, the number of 5-Sylow subgroups, $n_5$, must divide the order of the group and be congruent to 1 modulo 5. So, $n_5$ divides 6 and $n_5 \equiv 1 \pmod{5}$. The
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