(7) Sodium tetraphenylborate \( \mathrm{NaB}\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)_{4} \) is used as precipitant potassium. What is the \( \mathrm{w} / \mathrm{w} \% \) of \( \mathrm{K} 2 \mathrm{O}(\mathrm{F} \cdot \mathrm{wt}=94.20) \) in a fertilizer wh \( 0.4320 \mathrm{~g} \) sample gives \( 0.2138 \mathrm{~g} \) of \( \mathrm{K}_{2} \mathrm{~B}\left(\mathrm{C}_{6} \mathrm{H}_{5}\right) 4 \quad(\mathrm{~F} \cdot \mathrm{wt}=35 \) Ans.=???
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The molecular formula of the precipitate is \( \mathrm{K}_{2} \mathrm{~B}\left(\mathrm{C}_{6} \mathrm{H}_{5}\right) 4 \), which means it contains 2 moles of potassium for each mole of the compound. The molar mass of \( \mathrm{K}_{2} Show more…
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