7. [20%] The circuit below is a BJT differential amplifier with $V_{CC} = V_{EE} = 3 V$. The DC current source $I_{EE}$ is assumed ideal. The two transistors are identical, operate in the active region, and have $alpha = 0.99$ and $V_A = infty$. The thermal voltage $V_T$ is 26 mV at room temperature. The input is purely differential, i.e., $V_{ip} = -V_{im} = V_{id}/2$. a) Draw small-signal differential-mode half circuits of the differential amplifier. (5%) b) Express the differential voltage gain $A_d$, which is defined as $(V_{op} - V_{om})/V_{id}$, in terms of $I_{EE}$, $R_L$, $alpha$ and $V_T$. (6%) c) If $I_{EE} = 2mA$, what should be the value of $R_L$ to achieve $A_d = 40$? (4%) d) Choose another set of $I_{EE}$ and $R_L$ to maintain $A_d = 40$ while reducing the power consumption by half compared to the situation in part c). (2%) e) What is the maximum $A_d$ that the circuit can achieve if the DC levels at the output nodes $V_{op}$ and $V_{om}$ must be equal to or higher than 0V? (3%)
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imgur.com/5JZJZJL.png) b) The differential voltage gain Ad can be expressed as: Ad = -gmRc/(2Vr + 2gmRc) where gm is the transconductance of the transistor, given by gm = Ic/Vt, where Ic is the collector current and Vt is the thermal voltage. Since the two Show more…
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