00:01
Okay, so in this problem we are given a subspace that is a, b, c, d, where a minus 3b plus c is 0.
00:20
So by this equation, we know that c can be represented as 3b minus a.
00:30
So that means c can be determined by b and a.
00:34
So our vector, a, b, c, d can be rewrite.
00:45
We can rewrite this vector in terms of a, b, 3b minus a and d.
00:57
So notice that a, b and d are three variables here.
01:03
Well, c can be represented as a and b...