00:01
Hello students, given that f of x equals to x cube plus 2x square plus x divided by x square minus x minus 2.
00:17
First we set the denominator as 0.
00:21
So x square minus x minus 2 equals to 0.
00:24
This implies x minus 2 into x plus 1 equals to 0.
00:30
So x equals to 2 or x equals to minus 1.
00:37
So then say that the domain of f of x is all real numbers, all real numbers except x equals to 2 and x equals to minus 1.
01:04
Vertical asymptotes, vertical asymptotes occurs where the denominator is 0 and the numerator does not.
01:37
So the vertical asymptotes, so the vertical asymptotes exists at x equals to 2 and x equals to minus 1.
02:06
The horizontal asymptotes, the degree of the numerator 3 is greater than the degree of the denominator 2.
02:43
So there is no horizontal, horizontal asymptote.
02:53
Instead the function will have an, instead the function will have an oblique asymptote...