00:01
Hello students, let's begin with this question.
00:02
So, here in the first part we have to find out from the given pair of atoms these will have a known polar covalent or polar covalent or they will have the ionic bonds.
00:20
So, we have to find out that.
00:22
So, firstly in order to find out the bond between a pair of atoms.
00:27
So, here we have to observe the difference in the electronegativity of these given atoms.
00:37
So, now here if the if the this difference is difference is less than less than 0 .5 then the bond is the known polar covalent and if the difference is difference lies in between the 0 .5 and 1 .7 then the bond is the here the bond is the polar covalent and then if the difference is more than 1 .7 then the bond is the ionic bond.
01:28
So, now here firstly it is given that silicon and bromine.
01:31
So, here firstly the electronegativity of the silicon is equals to 1 .90 and the electronegativity of bromine is equals to 2 .96.
01:47
So, here the difference in the electronegativity is equals to this is equals to 2 .96 minus 1 .90.
02:00
So, this is equals to 1 .06.
02:03
So, this value is lies between the 0 .5 to 1 .7.
02:07
So, this will have a polar covalent bond.
02:12
Now the next is the lithium and fluorine here firstly the electronegativity of lithium is equals to lithium has 0 .98 and fluorine has electronegativity of 3 .98.
02:30
So, here the difference comes to be 3 .98 minus 0 .98.
02:36
So, this difference is equals to 3 .0.
02:39
So, this is more than 1 .7.
02:44
So, this will have the ionic bond.
02:51
Now in the next part we have to find out the intermolecular forces that are present in the given compounds.
03:02
So, first is the brf bromine fluoride.
03:05
So, brf.
03:06
So, here if we see this brf this is a polar molecule and this is a polar molecule...