Question

3) Draw the shear and bending moment diagrams for the beam and loading shown to the right. Determine: a) the maximum magnitude of the shear and of the bending moment, and b) the maximum normal stress due to bending. (Hint: you must find centroid of the trapezoid, and calculate $I$. Ans: $\bar{y} = 1.33$ in, $I_z = 4.063$ in$^4$) Ans. $|V_{max}| = 9280$ lb, $|M_{max}| = 28,224$ in-lb, $\sigma_{max} = 11.53$ ksi

          3) Draw the shear and bending moment
diagrams for the beam and loading shown to the
right. Determine: a) the maximum magnitude of
the shear and of the bending moment, and b) the
maximum normal stress due to bending. (Hint:
you must find centroid of the trapezoid, and
calculate $I$. Ans: $\bar{y} = 1.33$ in, $I_z = 4.063$ in$^4$)
Ans. $|V_{max}| = 9280$ lb, $|M_{max}| = 28,224$ in-lb,
$\sigma_{max} = 11.53$ ksi

3) Draw the shear and bending moment
diagrams for the beam and loading shown to the
right. Determine: a) the maximum magnitude of
the shear and of the bending moment, and b) the
maximum normal stress due to bending. (Hint:
you must find centroid of the trapezoid, and
calculate I. Ans: y̅ = 1.33 in, Iz = 4.063 in^4)
Ans. |Vmax| = 9280 lb, |Mmax| = 28,224 in-lb,
σmax = 11.53 ksi

Added by Corey K.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sikandar Baig

Step 1

The formula for the area of a trapezoid is (base1 + base2) * height / 2. In this case, the bases are 3 in and 8 in, and the height is 20 in. So the area is (3 + 8) * 20 / 2 = 11 * 20 / 2 = 110 in^2. 2) Show more…

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800 lb/in. 3) Draw the shear and bending moment diagrams for the beam and loading shown to the right. Determine: a) the maximum magnitude of the shear and of the bending moment, and b) the maximum normal stress due to bending. (Hint: you must find the centroid of the trapezoid and calculate I. Ans: y=1.33 in, I=4.063 in^4) Ans.|Vmax|=9280 lb, [Mmax|=28,224 in-lb, Ïƒmax = 11.53 ksi 3 in B 8 in. 20 in 2 in.