Question

(9.) \( 2^{x^{2}}=8^{2 x-3} \) 10. \( \frac{1}{4}\left(10^{-2 x}\right)=25\left(10^{x}\right) \) 11. \( 5-10^{2 x}=0 \) 12. \( 7^{-x}=9 \) 13. \( 3^{2(x-1)}=7^{2} \) 14. \( \left(\frac{1}{2}\right)^{-x+2}=8\left(2^{x-1}\right)^{3} \) 15. \( \frac{1}{3}=\left(2^{t-2}-1\right)^{-1} \) (16. \( \left(\frac{1}{3}\right)^{x}=9^{1-2 x} \)

          (9.) \( 2^{x^{2}}=8^{2 x-3} \)
10. \( \frac{1}{4}\left(10^{-2 x}\right)=25\left(10^{x}\right) \)
11. \( 5-10^{2 x}=0 \)
12. \( 7^{-x}=9 \)
13. \( 3^{2(x-1)}=7^{2} \)
14. \( \left(\frac{1}{2}\right)^{-x+2}=8\left(2^{x-1}\right)^{3} \)
15. \( \frac{1}{3}=\left(2^{t-2}-1\right)^{-1} \)
(16. \( \left(\frac{1}{3}\right)^{x}=9^{1-2 x} \)

(9.) 2^x^2=8^2 x-3
10. (1)/(4)(10^-2 x)=25(10^x)
11. 5-10^2 x=0
12. 7^-x=9
13. 3^2(x-1)=7^2
14. ((1)/(2))^-x+2=8(2^x-1)^3
15. (1)/(3)=(2^t-2-1)^-1
(16. ((1)/(3))^x=9^1-2 x

Added by Joanna A.

Beginning Algebra

Margaret L. Lial, John Hornsby 11th Edition

Chapter 2

Instant Answer

Solved by Expert Trinity Steen

06/19/2020

Step 1

Note that \(8 = 2^3\). Show more…

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(9.) \( 2^{x^{2}}=8^{2 x-3} \) 10. \( \frac{1}{4}\left(10^{-2 x}\right)=25\left(10^{x}\right) \) 11. \( 5-10^{2 x}=0 \) 12. \( 7^{-x}=9 \) 13. \( 3^{2(x-1)}=7^{2} \) 14. \( \left(\frac{1}{2}\right)^{-x+2}=8\left(2^{x-1}\right)^{3} \) 15. \( \frac{1}{3}=\left(2^{t-2}-1\right)^{-1} \) (16. \( \left(\frac{1}{3}\right)^{x}=9^{1-2 x} \)