Question

9. A series circuit consists of an ac source of variable frequency, a \( 115.0 \Omega \) resistor, a \( 1.25 \mu \mathrm{~F} \) capacitor, and a [1] \( 4.50-\mathrm{mH} \) inductor. The impedance of this circuit when the angular frequency of the ac source is adjusted to half the resonant angular frequency is a) \( 156.0 \Omega \) b) \( 166.0 \Omega \) c) \( 176.0 \Omega \) d) \( 146.0 \Omega \)

          9. A series circuit consists of an ac source of variable frequency, a \( 115.0 \Omega \) resistor, a \( 1.25 \mu \mathrm{~F} \) capacitor, and a
[1]
\( 4.50-\mathrm{mH} \) inductor. The impedance of this circuit when the angular frequency of the ac source is adjusted to half the resonant angular frequency is
a) \( 156.0 \Omega \)
b) \( 166.0 \Omega \)
c) \( 176.0 \Omega \)
d) \( 146.0 \Omega \)

9. A series circuit consists of an ac source of variable frequency, a 115.0 Ω resistor, a 1.25 μ F capacitor, and a
[1]
4.50-mH inductor. The impedance of this circuit when the angular frequency of the ac source is adjusted to half the resonant angular frequency is
a) 156.0 Ω
b) 166.0 Ω
c) 176.0 Ω
d) 146.0 Ω

Added by Francisco A.

University Physics with Modern Physics

Hugh D. Young 13th Edition

Chapter 31

Instant Answer

Solved by Expert Simran Hiranandani

08/06/2020

Step 1

- Resistor, \( R = 115.0 \, \Omega \) - Capacitor, \( C = 1.25 \, \mu\mathrm{F} = 1.25 \times 10^{-6} \, \mathrm{F} \) - Inductor, \( L = 4.50 \, \mathrm{mH} = 4.50 \times 10^{-3} \, \mathrm{H} \) Show more…

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9. A series circuit consists of an ac source of variable frequency, a \( 115.0 \Omega \) resistor, a \( 1.25 \mu \mathrm{~F} \) capacitor, and a [1] \( 4.50-\mathrm{mH} \) inductor. The impedance of this circuit when the angular frequency of the ac source is adjusted to half the resonant angular frequency is a) \( 156.0 \Omega \) b) \( 166.0 \Omega \) c) \( 176.0 \Omega \) d) \( 146.0 \Omega \)