Question

9. a. The average value of $f(x) = \frac{1}{\sqrt{x}}$ on the interval $[1, 4]$ is equal to b. Find the value c guaranteed by the Mean Value Theorem for the integrals such that $f_{avg} = f(c)$. The value c is equal to

          9. a. The average value of $f(x) = \frac{1}{\sqrt{x}}$ on the interval $[1, 4]$ is equal to 

b. Find the value c guaranteed by the Mean Value Theorem for the integrals such that $f_{avg} = f(c)$. The value c is equal to

9. a. The average value of f(x) = (1)/(√(x)) on the interval [1, 4] is equal to

b. Find the value c guaranteed by the Mean Value Theorem for the integrals such that favg = f(c). The value c is equal to

Added by Madeline P.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Donna Densmore

Step 1

The average value of f(x) = 1 on the interval [1, 4] is equal to the integral of f(x) divided by the length of the interval [1, 4]. The integral of f(x) = 1 on the interval [1, 4] is equal to the area under the curve f(x) = 1 on the interval [1, 4]. Since f(x) = Show more…

Show all steps

Thanks for your feedback!

a. The average value of f(x) = 1 on the interval [1, 4] is equal to b. Find the value c guaranteed by the Mean Value Theorem for the integral such that f(aug) = f(c). The value c is equal to