00:01
So the question is determine the x, y, z intercept of the plane and the plane that is given x, y, z is equal to 1, 8, 6 plus s 1, minus 12, minus 12 plus t 2, 4, minus 3.
00:39
So x, y, z is equal to 1 plus s plus 2t because 1 plus s plus 2t comma 8 minus 12s plus 4t comma 6 minus 12s minus 3t bracket close.
01:08
We all know that x intercept, x intercept, y and z both become 0.
01:20
So the 4t minus 12s plus 8 is the value of x is equal to 0, 6 minus 12s minus 3t is equal to 0.
01:33
This is the value of y and this is the value of z which is equal to 0, 7t plus 2 is equal to 0.
01:42
On solving these given equation, the value of t we get is minus 2y7.
01:48
The value of z is also equal to 0 that is 6 minus 12s plus 6 upon 7 is equal to 0.
01:57
Then we get s is equal to 4y7.
02:03
X is equal to 1 plus 4y7 minus 4y7 and we get x is equal to 1.
02:11
On putting all the values in x value then we get x is equal to 1.
02:18
At the y intercept, x and y, sorry x and z is equal to 0.
02:31
So the value of x is 1 plus s plus 2t is equal to 0 and the value of z is 6 minus 12s minus 3t is equal to 0.
02:46
4 minus 8s minus 2t is equal to 0.
02:51
5 minus 7s is equal to 0...