Question

9. Differentiate. No need to simplify your answers. (a) $y = e^2$ (b) $y = \sin^2 x$ (c) $y = 3^x$ (d) $y = \sqrt{2x - 1}$ (e) $y = \frac{x^2}{1 + x^2}$ (f) $y = e^{-x^2}$ (g) $y = x^2 \cos x$ (h) $y = \frac{1}{x}$ (i) $y = \tan x$ (j) $y = \ln x$ (k) $y = \arctan x$ (l) $y = \ln(x^2 + x)$

          9. Differentiate. No need to simplify your answers.
(a) $y = e^2$
(b) $y = \sin^2 x$
(c) $y = 3^x$
(d) $y = \sqrt{2x - 1}$
(e) $y = \frac{x^2}{1 + x^2}$
(f) $y = e^{-x^2}$
(g) $y = x^2 \cos x$
(h) $y = \frac{1}{x}$
(i) $y = \tan x$
(j) $y = \ln x$
(k) $y = \arctan x$
(l) $y = \ln(x^2 + x)$

9. Differentiate. No need to simplify your answers.
(a) y = e^2
(b) y = sin^2 x
(c) y = 3^x
(d) y = √(2x - 1)
(e) y = (x^2)/(1 + x^2)
(f) y = e^-x^2
(g) y = x^2 cos x
(h) y = (1)/(x)
(i) y = tan x
(j) y = ln x
(k) y = arctan x
(l) y = ln(x^2 + x)

Added by Cindy H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert M Hassan Anwar

02/14/2022

Step 1

Step 1: (a) y = e^2 y' = 0 Show more…

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9. Differentiate. No need to simplify your answers. (a) y = e^2 (b) y = sin^2x (c) y = 3^x (d) y = √2x-1 (e) y = x^2 / (1 + x^2) (f) y = e^-x^2 (g) y = x^2 cos x (h) y = 1/x (i) y = tan x (j) y = ln x (k) y = arctan x (l) y = ln(x^2 + x)