Question

Find vec{r}(t), given vec{r}(frac{pi}{2}) = <1, -2, frac{pi^2}{4}> and vec{r}'(t) = 2cos t vec{i} + 3sin t vec{j} + 2t vec{k}

Name: Find vecr(t), given vecr(fracpi2) = <1, -2, fracpi^24> and vecr'(t) = 2cos t veci + 3sin t vecj + 2t veck
Uploaded: 2022-07-16T16:03:31-08:00
Duration: 3 min 32 s
Channel: Adi S
Description: Find vecr(t), given vecr(fracpi2) = <1, -2, fracpi^24> and vecr'(t) = 2cos t veci + 3sin t vecj + 2t veck

          Find vec{r}(t), given vec{r}(frac{pi}{2}) = <1, -2, frac{pi^2}{4}> and vec{r}'(t) = 2cos t vec{i} + 3sin t vec{j} + 2t vec{k}

$Find vecr(t), given vecr(fracpi2) = <1, -2, fracpi^24> and vecr'(t) = 2cos t veci + 3sin t vecj + 2t veck$

Added by Gema B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

07/16/2022

Step 1

Step 1: Integrate each component of the given derivative r'(t): ∫2cos(t) dt = 2sin(t) + C1 ∫3sin(t) dt = -3cos(t) + C2 ∫2t dt = t^2 + C3 Show more…

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Find r(t), given r(pi/2) = <1, -2, pi^2/4> and r'(t) = 2cos(t)i + 3sin(t)j + 2tk.

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Find vec{r}(t), given vec{r}(frac{pi}{2}) = <1, -2, frac{pi^2}{4}> and vec{r}'(t) = 2cos t vec{i} + 3sin t vec{j} + 2t vec{k}

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