8. If individuals IV-3 and IV-4 marry, what is the...

8. If individuals IV-3 and IV-4 marry, what is the probability that their first child will have the disease? A. 1/32 B. 1/48 C. 1/64 D. 1/12 E. 1/16 9. Statistically, this trait has a probability of 0.0001 in the population in which these families live. If IV5 is married with a man who is also in this community. What is the probability if your first child has this trait? A. 0.0825% B. 0.0413% C. 0.165% D. 0.123% E. 0.246% 10. If the disease is inherited as an autosomal dominant trait with 50% penetrance, then what would be the possibility that the first child from the marriage of IV3 and IV4 shows this disease? A 1.0 B. 0.0417 C. 0.0313 D. 0.1342 E. None of the answers.

Transcript

00:01 Now let's answer this question let's talk about in here it's okay.

00:04 This is an auto -summar recessive disorder, so this is going to be homo -sidu -besessive.

00:08 In this case, here are going to be both heterocyboes because this man is homoseive -de -resensive.

00:13 So it means that remember that a person in here is one from each parent, so it means that one recessive -a came from this parent, and one -rescent -a came from this parent.

00:22 So both of them should be hetero -cybos.

00:25 Now, it says if individuals, this and this, maui, what is the probability that their first child, will have a disease.

00:31 So in order for healthy people to have the disease, they should be heterocygoy.

00:37 Okay? in order for them to have a child with a disease.

00:40 So you want them to be both heterosigos.

00:43 And what must happen in order for them to be heterotrigal? well, first from across we have a heterocybinon hydrocygos with a neutral cygos.

00:51 You're going to have.

00:52 Homozygos dominant hittrosaigos is a more psycho obsessive.

00:57 In this case, you want this person to be a cavity, it means a heterocylus.

01:03 So out of three possibilities, we're not going to consider this because we already know that this person is healthy.

01:08 Okay, so out of three possibilities, one and two are going to be.

01:11 Hitrogygos.

01:12 So you have two thirds chances for this woman to be heterocylus.

01:16 Now this person comes from out of the family.

01:18 So he is homoseouseloma.

01:23 Then for a cross between a homoseousel dominant and a heterocygote.

01:28 You have homosegos, homoegos domino, homozygos, heterocygote, heterocygots, and heterocygots.

01:33 So all four possibilities two are going to be cagers in this heterozygos, it means one half.

01:38 So you have one half chances for this woman to be heterozygos, and this man is also homozygous, dominant.

01:44 So you have one half more chances for this man to be heterozygotes, okay? one half chances.

01:53 So in total you have two thirds multiplied by one half and by one half, and this is equal to one six for this man to be heterozygsoyx.

02:04 Let's do the same for this woman here.

02:07 This man is affected, so it means that this woman is going to be for sure heterocygous because this man only has greciousity to transmit to this woman.

02:17 So this man is homozygous dominant, it means we have this panel square.

02:21 And from this panel square, two out of four possibilities are going to be heterocycos, it means one -half.

02:29 So you have one -half chances for this man to be hetero -sigo -segos.

02:35 And then you have this woman that is homozygos dominant.

02:38 You have again the same cross.

02:40 It means you have 1 half chances for this woman to be heterozygote.

02:44 So you have to multiply 1 half by 1 half and this is equal to 1 quarter.

02:49 So you have 1 quarter for the woman to be hydrozygos and 1 6 for this man to be hydrozygos.

02:55 Then you have this panel in a square and paying for this cross...

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