Find an equation of the plane through the point P (-2, 4, -1) and the line of intersection of the planes 5x - y - 12z = 15 and 2x + 3y + 2z = 6.
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- The normal vector of the plane \(5x - 12z = 15\) is \(\mathbf{n_1} = (5, 0, -12)\). - The normal vector of the plane \(2x + 3y + 2z = 6\) is \(\mathbf{n_2} = (2, 3, 2)\). Show more…
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