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Score on last try: 2.5 of 10 pts. See Details for more. > Next question Get a similar question You can retry this question below $\int \frac{\sqrt{9x^2 - 49}}{x^3} dx$ (A) Which trig substitution is correct for this integral? $x = \frac{7}{3} sec(\theta)$ $x = \frac{7}{9} sec(\theta)$ $x = \frac{7}{3} sin(\theta)$ $x = \frac{49}{9} sec(\theta)$ $x = \frac{7}{3} sec(\theta)$ (B) Which integral do you obtain after substituting for $x$? Note: to enter $\theta$, type the word theta. $\int \text{} d\theta$ (C) What is the value of the above integral in terms of $\theta$? $\text{} + C$ (D) What is the value of the original integral in terms of $x$? Note: WAMAP does not recognize the inverse secant (arcsec) function. You will need to use another inverse trig function when you fill in your answer below. $\frac{9}{14} \tan^{-1}(\frac{\sqrt{9x^2 - 49}}{7}) - \frac{\sqrt{9x^2 - 49}}{2x^2} + C$

          Score on last try: 2.5 of 10 pts. See Details for more.
> Next question Get a similar question You can retry this question below
$\int \frac{\sqrt{9x^2 - 49}}{x^3} dx$
(A) Which trig substitution is correct for this integral?
$x = \frac{7}{3} sec(\theta)$
$x = \frac{7}{9} sec(\theta)$
$x = \frac{7}{3} sin(\theta)$
$x = \frac{49}{9} sec(\theta)$
$x = \frac{7}{3} sec(\theta)$
(B) Which integral do you obtain after substituting for $x$?
Note: to enter $\theta$, type the word theta.
$\int \text{________} d\theta$
(C) What is the value of the above integral in terms of $\theta$?
$\text{________} + C$
(D) What is the value of the original integral in terms of $x$?
Note: WAMAP does not recognize the inverse secant (arcsec) function. You will need to use another inverse trig function when you fill in your answer below.
$\frac{9}{14} \tan^{-1}(\frac{\sqrt{9x^2 - 49}}{7}) - \frac{\sqrt{9x^2 - 49}}{2x^2} + C$

Score on last try: 2.5 of 10 pts. See Details for more.
> Next question Get a similar question You can retry this question below
∫(√(9x^2 - 49))/(x^3) dx
(A) Which trig substitution is correct for this integral?
x = (7)/(3) sec(θ)
x = (7)/(9) sec(θ)
x = (7)/(3) sin(θ)
x = (49)/(9) sec(θ)
x = (7)/(3) sec(θ)
(B) Which integral do you obtain after substituting for x?
Note: to enter θ, type the word theta.
∫ dθ
(C) What is the value of the above integral in terms of θ?
+ C
(D) What is the value of the original integral in terms of x?
Note: WAMAP does not recognize the inverse secant (arcsec) function. You will need to use another inverse trig function when you fill in your answer below.
(9)/(14)tan^-1((√(9x^2 - 49))/(7)) - (√(9x^2 - 49))/(2x^2) + C

Added by Nicholas V.

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