Question

A 0.500 kg soccer ball is kicked and hits a 2.5 kg stationary tetherball hanging from a 0.500 m tether, resulting in a perfectly elastic collision. If the tetherball swings out at a maximum angle of 55.9°, what was the soccer ball's velocity before the collision?

          A 0.500 kg soccer ball is kicked and hits a 2.5 kg stationary tetherball hanging from a 0.500 m tether, resulting in a perfectly elastic collision. If the tetherball swings out at a maximum angle of 55.9°, what was the soccer ball's velocity before the collision?
        
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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A 0.500 kg soccer ball is kicked and hits a 2.5 kg stationary tetherball hanging from a 0.500 m tether, resulting in a perfectly elastic collision. If the tetherball swings out at a maximum angle of 55.9°, what was the soccer ball's velocity before the collision?
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Transcript

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00:01 Hi, in this question we have a soccer ball having mass m1 given as 0 .5 .00 kg and it is kicked and it hits a stationary tether ball having mass m2 given as 2 .5 kg.
00:20 So this second ball is hanging from a 0 .5 meter tether.
00:29 So we have a 0 .5 .00 meter.
00:29 So we have l given as 0 .500 meter such that the collision is a perfectly elastic collision.
00:40 Now if the tether ball swings out at a angle theta which is given as 55 .9 degrees, we have to calculate the soccer ball's velocity before the collision.
00:54 Now, if we use law of conservation of energy, we can write half of mv square equals to m gl into 1 minus cos of theta.
01:09 So from here we can solve the value for v, which is the speed after collision equals to under root twice of gl into 1 minus cause of theta...
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