A 0.400 kg soccer ball is kicked and hits a 2 kg stationary...

Name: A 0.400 kg soccer ball is kicked and hits a 2 kg stationary tether ball hanging from a 0.660 m tether resulting in a perfectly elastic collision. If the tether ball swings out at a maximum angle of 67.9°, what was the soccer ball's velocity before the collision?
Uploaded: 2022-12-13T20:35:26-08:00
Duration: 3 min 15 s
Channel: Sri K
Description: A 0.400 kg soccer ball is kicked and hits a 2 kg stationary tether ball hanging from a 0.660 m tether resulting in a perfectly elastic collision. If the tether ball swings out at a maximum angle of 67.9°, what was the soccer ball's velocity before the collision?

A 0.400 kg soccer ball is kicked and hits a 2 kg stationary tether ball hanging from a 0.660 m tether resulting in a perfectly elastic collision. If the tether ball swings out at a maximum angle of 67.9°, what was the soccer ball's velocity before the collision?

Transcript

00:01 So here in this version we are given a pendulum.

00:05 Here this is making an angle of theta.

00:08 This is l.

00:09 This is let's say point p.

00:12 This is m.

00:13 This is distance l minus h.

00:16 This distance is h.

00:19 So from here we can say that let the initial velocity before collision is u1 and after collision is v1.

00:27 And the initially before collision is 0, then v2.

00:30 U2 is equal to 0 and v2 is here.

00:33 So from here we can say that according to conservation of momentum m1 u1 plus m2 u2 will be equals to m1 v1 plus m2 v2 where m1 is given which is 0 .4 kg and m2 is 2 so from here u2 is equal to 0 so we can write it as m1 v1 plus m2 b2 or we can write it as m1 v1 plus m2 b2 or we can write it as of u1 minus v1 it will be equals to m2 v2 let's say this will be the equation number 1 so here we are applying energy conservation so according to energy conservation before and extra coefficient this will be 1 divided by 2 m1 u1 raise to the power 2 plus 1 divided by 2 m2 u 2 raise to the power 2 this will be 1 divided by 2 m1 v1 raised to the power 2 plus 1 divided by 2 m2 v2 raise to the power 2 so from here we can say that m2 v2 multiply by the u1 plus v1 will be equals to m2 v2 so from here we can say that u1 plus v1 is equal to v2 let's say this will be the equation number 2 and here multiply by 2 with the m1 so we can say that m1 u1 plus v1 is equals to m1 v2 let's say this will be digression number 3rd so from here we can say that from equation first plus 3, 1 plus 3 we get the value of u1 as m1 plus m2 multiplied by the v2 divided by 2 of m1.

02:16 This will be the equation number 4...

Question

A 0.400 kg soccer ball is kicked and hits a 2 kg stationary tether ball hanging from a 0.660 m tether resulting in a perfectly elastic collision. If the tether ball swings out at a maximum angle of 67.9°, what was the soccer ball's velocity before the collision?

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