00:01
Hello students, in this question we have given multiple subparts.
00:06
For that first we need to find angular velocity that is omega is equal to square root of k by m.
00:15
Now putting the values here we get 460 divided by 0 .700 that gives angular velocity will be 25 .63 radian per second.
00:27
Now to find first a part in which we have to calculate the maximum speed of the grinder.
00:34
Now using the formula for maximum speed that is multiplication of amplitude and angular velocity.
00:42
Substituting the values we get 4 into 10 to the power minus 2 multiply of 25 .63 after solving this we get maximum velocity will be 1 .025 meter per second.
01:00
Now in v part we have to calculate the speed of the grinder when it is here x is given as 1 .6 into 10 to the power minus 2 meter.
01:14
Now using the formula v is equal to omega square root of amplitude square minus x square.
01:24
Now substituting the values here we get 25 .63 square root of 4 into 10 to the power minus 2 whole square minus minus of 1 .60 into 10 to the power minus 2 square.
01:42
Now after solving this we get speed will be equal to 0 .9396 meter per second.
01:52
Now for in c part we have to find the acceleration.
01:58
So using the formula for maximum acceleration that is a is equal to a multiplication of amplitude square of angular velocity.
02:10
Now substituting the values here we get 4 into 10 to the power minus 2 into 25 .63 square...