00:01
Hello everyone we are going to understand this question here given in the question given mass of ball mass of ball m is equal to 0 .82 kg and initial speed is given 0 initial speed u is equal to 0 and height of point is given 4 .6 meter height of point h is equal to 4 .6 meter and sorry let it is represented by h1 and h2.
01:07
H1 is equal to 4 .6 meter and rebound height rebound height h2 is equal to 1 .5 meter now calculation for the first rebound calculation before rebound calculation before rebound now let the speed of ball let the speed of ball at the time of hitting the ground be v at the time of hitting the ground setting the ground v v.
02:33
Now v square is equal to u square plus 2 g h.
02:43
Now again we can write v square is equal to u is 0 plus 2 into 9 .8 into value of h that is 4 .6 now again we can write v square is equal to square root of sorry v is equal to square square root of 90 .16 meter per second.
03:23
Now doing further calculation, v is equal to 9 .5 meter per second.
03:32
9 .5 meter per second.
03:37
Let the initial speed after rebound.
03:42
Let the initial speed after rebound be u1 and and when it reached to the first.
04:08
To the maximum height and when it reached when it reached to the maximum height let the initial speed after rebound be u1 and when it reach to the maximum height velocity will be zero velocity at the top velocity at the top be zero now b1 square is equal to u1 square minus 2 into h1.
05:13
Here final velocity is 0 and initial velocity we have to find minus 2 into 9 .8 into h1 is 1 .5.
05:24
Now doing further calculation u1 square is equal to 3 into 9 .8...