A 10-mm cube of copper metal is placed in 250 mL of 12 M nitric acid at 25°C and the reaction below occurs:
Cu(s) + 4H+(aq) + 2NO3(aq) -> Cu²+(aq) + 2NO2(g) + 2H2O(l)
At a particular instant in time, nitrogen dioxide is being produced at the rate of 2.2 x 10⁻⁴ M/min. At this same instant, what is the rate at which copper is produced in M/min?
Do not write unit in answer. Report your answer with five places past the decimal point.