Question

A 10.0 -g bullet is fired into a stationary block of wood having mass $m=5.00 \mathrm{kg}$ . The bullet imbeds into the block. The speed of the bullet-plus-wood combination immediately after the collision is 0.600 $\mathrm{m} / \mathrm{s}$ . What was the original speed of the bullet?

Name: A 10.0 -g bullet is fired into a stationary block of wood having mass m=5.00 kg . The bullet imbeds into the block. The speed of the bullet-plus-wood combination immediately after the collision is 0.600 m / s . What was the original speed of the bullet?
Uploaded: 2022-06-26T08:57:32-08:00
Duration: 2 min 17 s
Channel: Priyanka Sadarangani
Description: A 10.0 -g bullet is fired into a stationary block of wood having mass m=5.00 kg . The bullet imbeds into the block. The speed of the bullet-plus-wood combination immediately after the collision is 0.600 m / s . What was the original speed of the bullet?

          A 10.0 -g bullet is fired into a stationary block of wood having mass $m=5.00 \mathrm{kg}$ . The bullet imbeds into the block. The speed of the bullet-plus-wood combination immediately after the collision is 0.600 $\mathrm{m} / \mathrm{s}$ . What was the original speed of the bullet?

Added by Jason M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Priyanka Sadarangani

06/26/2022

Step 1

0 \, \text{g} = 0.01 \, \text{kg}\) - Mass of the block, $m_2 = 5.00 \, \text{kg}$ - Initial velocity of the bullet, $v_1 = ?$ - Initial velocity of the block, $v_2 = 0 \, \text{m/s}$ - Final velocity of the bullet-block system after collision, \(V = 0.600 \, Show more…

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A 10.0 -g bullet is fired into a stationary block of wood having mass $m=5.00 \mathrm{kg}$ . The bullet imbeds into the block. The speed of the bullet-plus-wood combination immediately after the collision is 0.600 $\mathrm{m} / \mathrm{s}$ . What was the original speed of the bullet?