A 10.0 -g bullet is fired into a stationary block of wood (m= 5.00 kg ). The relative motion of

Name: Problem 17, Chapter 9: Physics for Scientists and Engineers with Modern Physics
Uploaded: 2020-09-12T10:04:36-08:00
Duration: 35 s
Channel: Mayukh Banik
Description: A 10.0 -g bullet is fired into a stationary block of wood (m= 5.00 kg ). The relative motion of the bullet stops inside the block. The speed of the bullet-plus-wood combination immediately after the collision is 0.600 m / s . What was the original speed of the bullet?

step 1 Conservation of momentum is that initial momentum equals final momentum. So the initial momentum

Question

A 10.0 -g bullet is fired into a stationary block of wood $(m=$ 5.00 $\mathrm{kg}$ ). The relative motion of the bullet stops inside the block. The speed of the bullet-plus-wood combination immediately after the collision is 0.600 $\mathrm{m} / \mathrm{s}$ . What was the original speed of the bullet?

   A 10.0 -g bullet is fired into a stationary block of wood $(m=$ 5.00 $\mathrm{kg}$ ). The relative motion of the bullet stops inside the block. The speed of the bullet-plus-wood combination immediately after the collision is 0.600 $\mathrm{m} / \mathrm{s}$ . What was the original speed of the bullet?

Physics for Scientists and Engineers with Modern Physics

Paul Tipler, Gene… 6th Edition

Chapter 9, Problem 17

Instant Answer

Solved by Expert Mayukh Banik

09/12/2020

Step 1

According to this law, the total momentum before the collision is equal to the total momentum after the collision. Show more…

Show all steps

Thanks for your feedback!

A 10.0 -g bullet is fired into a stationary block of wood $(m=$ 5.00 $\mathrm{kg}$ ). The relative motion of the bullet stops inside the block. The speed of the bullet-plus-wood combination immediately after the collision is 0.600 $\mathrm{m} / \mathrm{s}$ . What was the original speed of the bullet?

Play audio

Feedback

Mayukh Banik and 94 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Conservation of Momentum

This fundamental principle states that in a closed system with no external forces, the total momentum remains constant before and after a collision. It is used to relate the momentum of individual objects before impact to the momentum of the combined mass after impact, allowing for the calculation of unknown velocities in collision problems.

Completely Inelastic Collision

In a completely inelastic collision, the colliding objects stick together and move as one mass after the impact. Although momentum is conserved in such collisions, kinetic energy is not conserved due to energy dissipating into other forms like heat or deformation. This concept is critical for understanding and analyzing collisions where objects become embedded or move together after the impact.

Please give Ace some feedback