A 1000-kg car moving with a speed of 70 km/h goes up a circular section of a road with radius R = 200 m, as shown in the figure below. The normal force (in N) on the car when ? = 60° is a) 6600 b) 4900 c) 1890 d) 8490 e) 3011
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Step 1
First, we need to convert the speed from km/h to m/s. We know that 1 km = 1000 m and 1 hour = 3600 seconds. So, 70 km/h = 70 * 1000 / 3600 = 19.44 m/s. Show more…
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