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e=96% e=98% P_{OUT} n_{OUT} T_{OUT} TV=120.5 e=72% e=98% P_{IN} n_{IN} T_{IN} A 1.25 HP electric motor rotating at 1,250 RPM provides power to a gear train as illustrated. The individual stage efficiencies and associated Train Value (TV) for the entire gear train is as shown. The output torque (in in-lb) is: 5,039.45 9,678.81 9,124.71 7,591.50

          e=96%
e=98%
P_{OUT}
n_{OUT}
T_{OUT}
TV=120.5
e=72%
e=98%
P_{IN}
n_{IN}
T_{IN}
A 1.25 HP electric motor rotating at 1,250 RPM provides power to a gear train
as illustrated. The individual stage efficiencies and associated Train Value (TV)
for the entire gear train is as shown. The output torque (in in-lb) is:
5,039.45
9,678.81
9,124.71
7,591.50
        
Show more…
e=96%
e=98%
POUT
nOUT
TOUT
TV=120.5
e=72%
e=98%
PIN
nIN
TIN
A 1.25 HP electric motor rotating at 1,250 RPM provides power to a gear train
as illustrated. The individual stage efficiencies and associated Train Value (TV)
for the entire gear train is as shown. The output torque (in in-lb) is:
5,039.45
9,678.81
9,124.71
7,591.50

Added by Sandra C.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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A 1.25 HP electric motor rotating at 1,250 RPM provides power to a gear train as illustrated. The individual stage efficiencies and associated Train Value (TV) for the entire gear train are as shown. The output torque (in in-lb) is: 5,039.45 9,678.81 9,124.71 7,591.50
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Transcript

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00:01 In this question it is told that a projectile has the same range for two angles of projection and we have given that t1 and t2 be the time of flight in the two cases then we have to find the range.
00:13 So let the first projectile is projected at angle of teta 1 and it reaches the ground at a range that is given by r and it is told that the second projectile is projected and it also has the same range.
00:34 So this is also we have given the value of r...
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