00:01
Hi students in this question, it is given that a car and a truck is undergoing condition and in the first part of the question we are asked to find out the final velocity v2 associated with the truck.
00:10
And here in order to find the value of v2 we have to use the law of conservation of momentum.
00:15
And according to the law of conservation of momentum, we can say that the value of m1 into u1 plus m2 into u2 will be equal to m1 into v1 plus m2 into v2.
00:28
And here by rearranging this equation we get the equation of final velocity of the truck b2 to be equal to m1 into u1 plus m2 into u2 minus m1 into v1 the whole divided by m2 and in this case m1 corresponds to the mass of the car which is taken to be 1 ,285 kilogram on the other hand m2 corresponds to the mass of the truck which is taken to be 8 ,200 kilogram now the initial the initial velocity of the car is taken as u1, which is equal to 25 m per second.
01:03
On the other hand, the initial velocity of the truck is taken as u2, which is equal to 20 meter per second.
01:09
And here, the final velocity of the car is taken as b1, whose value is given to be 18 meter per second.
01:15
On the other hand, the final velocity b2 of the truck has to be determined.
01:19
And here, by substituting these values in the evo equation, we get b2 to be equal to 1 ,285 into 25...