A 150-kg block slides across ice and comes to a stop in 12.50 m. A) The coefficient of kinetic friction between ice and the block is 1.800. What is the frictional force acting on the block? B) What was the speed of the block before it stopped?
Added by Bradley A.
Step 1
Since the block is sliding horizontally, the normal force is equal to the weight of the block, which is: normal force = mass x gravity normal force = 150 kg x 9.81 m/s^2 normal force = 1471.5 N Now we can calculate the frictional force: frictional force = Show more…
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