00:01
In this problem, we have been given that on an inclined plane, there is an object of mass 15 kg.
00:08
So let's take the mass represented by m and that's 15 kg.
00:13
And this object is accelerating down at the rate of 0 .8 meter per second square.
00:19
So this is the acceleration down the incline.
00:22
Considering 32 degree as the angle of incline, we need to determine here the coefficient of kinetic friction.
00:30
So let's consider that kinetic friction coefficient as mu.
00:34
And let's see the complete force that's acting on this object.
00:38
So there will be a normal force and there will be weight in the vertically downward direction.
00:43
Plus there will be a friction force which will oppose the motion of an object.
00:48
So that will be mu times the normal force.
00:51
And here we take the component of the weight along the incline and perpendicular to the incline.
00:56
So we observe that geometrically this angle comes out to to be 58 degree and hence we can see that this angle is 32 degree and now we project the weight.
01:07
So that will be mg cos 32 degree in this direction and mg sign 32 degree in this direction.
01:16
So we observe that the net force in the direction of acceleration that comes out to be m g sign 32 degree minus mu times the normal force...