Given:
Initial velocity, \(u = 80 \, \text{m/s}\)
Distance traveled, \(s = 40 \, \text{m}\)
Using the equation \(v^2 = u^2 + 2as\), where \(v = 0\) (final velocity as the mass comes to a stop), we can solve for acceleration \(a\):
\[0 = (80)^2 + 2a(40)\]
\[0 =
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