A 20.0 mL sample of 0.1015 M nitric acid is introduced into a flask, and water is added until the volume of the solution reaches 0.737 L. What is the concentration of nitric acid in the final solution?
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Step 1
0 mL sample. Given: Volume of nitric acid solution = 20.0 mL = 20.0 x 10^-3 L Concentration of nitric acid = 0.1015 M Moles of nitric acid = concentration x volume Moles = 0.1015 mol/L x 20.0 x 10^-3 L Moles = 2.03 x 10^-3 mol Show more…
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