A 220 -mH inductor carries 350 mA. How much energy must be supplied to the inductor in raising the current to 850 mA?
Added by Jenna O.
Step 1
Given: Inductance, L = 220 mH = 220 * 10^-3 H Initial current, I1 = 350 mA = 350 * 10^-3 A Using the formula for energy stored in an inductor: Initial energy, U1 = 0.5 * L * I1^2 U1 = 0.5 * 220 * 10^-3 * (350 * 10^-3)^2 U1 = 0.5 * 220 * 10^-3 * 0.1225 U1 = Show more…
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