00:02
Hello, in this question we will use the formula m1 v1 by n1 is equal to m2 v2 by n2.
00:12
Okay, so first let's write the balanced chemical equation for the reaction.
00:16
So it is n -a -o -h plus hcl gives us nacl plus h2.
00:27
Right? so this is the balanced chemical equation.
00:31
Okay, so this is already balanced.
00:34
So we can see that the molar ratio is 1 is to 1 right so 1 mole of noh reacts with 1 more of hcl to give 1 mole of nacl plus 1 more of h2 right so it means that n1 and n2 are 1 each okay let's try fill fill the values for m1 and v1 okay and then we have to find the grams of n aohh right so we'll find that okay so let's try to fill so m1 is equal to concentration of which we have to find so we are supposed to find the concentration of an aoh okay then v1 is the volume of an a that we already know then m2 is the concentration of hl v2 is the volume of hcl so now we can substitute the values so m1 we have to find then v1 which is the volume of n a which is given so it is 23 .15 right and n1 is 1 is equal to now concentration of hcl, concentration of hcl is 0 .131 multiplied by v2 which is volume of hcl, volume of hcl is 23 point, no not 23 but 27 .46 right? 27 .46 right? so this is the volume of hcl and divided by 1.
02:34
Right so now from here we'll calculate the concentration of nah .h right? so this will be 0 .131 multiplied by 27 .46 divided by 23 .15.
02:52
Right.
02:52
So this will give us the concentration of n .a .o .h.
02:56
Right.
02:59
So when we solve this using a calculator, we get 0 .155 molar.
03:06
Right.
03:06
So this is the concentration of nah .h...