00:01
Hello students, in the question we are given power supply with voltage v equal to 240 volts, frequency f equal to 60 hertz and current i through load equal to 200 amperes.
00:17
Here we have lagging cos phi equal to 75 percent or we can write 0 .75.
00:26
Here we have active component of i m equal to i m cos phi.
00:45
So this is equal to 200 amperes into 0 .75.
00:50
This is equal to 150 amperes.
00:54
Also we have cos phi with capacitance given as 90 percent.
01:02
So this is equal to 0 .90.
01:05
Here we have active component of current i is equal to i cos phi.
01:19
So this is equal to i into 0 .90.
01:25
Here in this phasor diagram active component it is equivalent to this distance o a.
01:38
So here we can write 0 .9 into i is equal to 150 amperes or from here we get i is equal to 150 divided by 0 .9.
01:51
So this is equal to 166 .67 amperes.
01:56
Also here we have reactive component of i m equal to i m sin phi m.
02:15
So here we have this is equal to 200 into under root 1 minus 0 .75 square because we know sin square phi is equal to 1 minus cos square phi or we can say sin phi is equal to under root 1 minus cos square phi.
02:41
So this comes out to be equal to 132 .28 amperes...