Question

A 2 kg block of ice slides along a level floor for a distance of 6.5 m, decreasing its speed from 4.3 m/s to 1.8 m/s. a) How much kinetic energy was lost by the ice over that distance? b) Determine the force of friction acting to slow down the block of ice. c) What is the coefficient of sliding friction between the block and the floor?

Name: a 2kg block of ice slides along a level floor for a distance of 65mdecreasing its speed from 43ms to 18ms a how much k e was lost by ice over that distance b determine force of friction acti 03888
Uploaded: 2022-08-07T13:07:55-08:00
Duration: 4 min 25 s
Channel: Sahil Kumar
Description: a 2kg block of ice slides along a level floor for a distance of 65mdecreasing its speed from 43ms to 18ms a how much k e was lost by ice over that distance b determine force of friction acti 03888

          A 2 kg block of ice slides along a level floor for a distance of 6.5 m, decreasing its speed from 4.3 m/s to 1.8 m/s. a) How much kinetic energy was lost by the ice over that distance? b) Determine the force of friction acting to slow down the block of ice. c) What is the coefficient of sliding friction between the block and the floor?

Added by Robert H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sahil Kumar

08/07/2022

Step 1

Given: Initial speed, \( u = 4.3 \, m/s \) Final speed, \( v = 1.8 \, m/s \) Mass of the block, \( m = 2 \, kg \) Distance, \( s = 6.5 \, m \) Using the formula for lost kinetic energy: \[ \text{Lost Kinetic Energy} = \frac{1}{2} m (v^2 - u^2) \] Substitute the Show more…

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A 2 kg block of ice slides along a level floor for a distance of 6.5 m, decreasing its speed from 4.3 m/s to 1.8 m/s. a) How much kinetic energy was lost by the ice over that distance? b) Determine the force of friction acting to slow down the block of ice. c) What is the coefficient of sliding friction between the block and the floor?