00:01
So here we are discussing about this cycle.
00:04
So here this side is representing temperature.
00:07
This is as so here the cycle is moving in this way.
00:12
Let's say this is point 1, this is 2, this is 3 and this is 4.
00:16
So here we are given the value of t1 which is equals to 310 kelvin and that of p1 is 100 kiosk.
00:25
The value for t2 is temperature 2 is 650 kelvin.
00:30
And p2 here is 900 kilo pascal so from here we can say that nr is given which is 0 .8 and t is also given which is 1400 kelvin and t here is 0 .9 so this values are given in the table so here we can say that pr 4 is equal to p r3 divided by the rp where the p r3 value is given which is equal to 4 15 point five so this comes out to be 450 .5 divided by the value of r p is is that of in the terms of p2 so from here we can say that 450 .5 divided by the rp is 900 divided by the 100 so after solving this we get the value as 50 .06 so the value of p r4 is 50 .06 so the value of p r4 is 50 .06 now h4 is given which is 832 .46 kilojoule per kg.
01:43
So we can say that this is at 50 .06 pr4.
01:49
So here h4 dash is equals to h3 minus and t, h3 minus h4.
02:00
So putting values here, this is 1515 .45 .42 minus 0 .9 .9.
02:06
Multiplied by the 1515 .42 minus 832 .46 so after solving all this value we get the value of h4 dash which is equals to 900 .76 kilojoules per kilogram so from here we can say it h1 is given in this way 300 kelvin is equals to 310 .24 kilojoule per kilogram and we can say that h2 here is 6 ccfcccc .9 .859 .84 kilojou per kg...