A 360-turn coil with an average radius of 0.030 m is placed in a uniform magnetic field so that p = 39". The field increases at a rate of 0.315 T/s. What is the magnitude of the resulting emf? Express your answer with the appropriate units.
Added by Ryan D.
Step 1
The magnetic flux through a coil is given by the formula: Φ = B * A * cos(θ) where: Φ = magnetic flux B = magnetic field strength A = area of the coil θ = angle between the magnetic field and the normal to the coil Given: B = 0.315 T (magnetic field strength) A = Show more…
Show all steps
Your feedback will help us improve your experience
Ankur S and 61 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A fixed 16.3-cm-diameter wire coil is perpendicular to a magnetic field of 0.74 T pointing up. In 0.25 s, the field is changed to 0.22 T pointing down. What is the average induced emf in the coil? Express your answer to two significant figures and include the appropriate units.
Ankur S.
A fixed 18.1-cm-diameter wire coil is perpendicular to a magnetic field 0.80 T pointing up. In 0.30 s, the field is changed to 0.34 T pointing down. Part A: What is the average induced emf in the coil?
Adi S.
A circular coil of wire has 300 turns and an average radius of 2.00 cm. The coil is placed at a 60° angle to the uniform magnetic field between the two poles of a large electromagnet. The strength of the field changes at a rate of -0.300 T/s. What is the magnitude of the resulting induced emf? 0.098 V 0.067 V 0.052 V 0.002 V
Prabhu R.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD