61\) kg, \(g = 9.8\) m/s\(^2\), \(h = 0.071\) m.
Given that the initial velocity of the bullet is 0 m/s (since it starts from rest), we can solve for the final velocity \(v\).
\[1.61 \times 9.8 \times 0.071 = \frac{1}{2} \times 1.61 \times v^2\]
\[v =
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