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Tasnim Hossain

Tasnim H.

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Questions asked

INSTANT ANSWER

What is the net electric force on the charge at the origin? The value of the Coulomb constant is \( 8.99 \times 10^{9} \mathrm{~N} \cdot \mathrm{m}^{2} / \mathrm{C}^{2} \). Answer in units of N. 006 (part 2 of 4 ) \( 10.0 \) points What is the direction of this force (as an angle between \( -180^{\circ} \) and \( +180^{\circ} \) measured from the positive \( x \)-axis, with counterclockwise positive)? Answer in units of \( ^{\circ} \). 007 (part 3 of 4 ) \( 10.0 \) points What is the magnitude of the net electric field at the position of the charge at the origin? Answer in units of \( \mathrm{N} / \mathrm{C} \). 008 (part 4 of 4 ) \( 10.0 \) points What is the direction of the net electric What is the direction of the net electric field (as an angle between \( -180^{\circ} \) and \( +180^{\circ} \) measured from the positive \( x \)-axis, with counterclockwise positive). Answer in units of \( ^{\circ} \).

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INSTANT ANSWER

Consider charges placed at the corners of a rectangle. Find the electric potential at point \( P \) due to the grouping of charges at the other corners of the rectangle. The Coulomb constant is \( 8.98755 \times 10^{9} \mathrm{~N} \cdot \mathrm{m}^{2} / \mathrm{C}^{2} \) and the acceleration due to gravity \( 9.8 \mathrm{~m} / \mathrm{s}^{2} \). Answer in units of \( \mathrm{V} \). Answer in units of \( V \)

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INSTANT ANSWER

Plot the point \( \left(-2,-\frac{\pi}{6}\right) \), given in polar coordinates, and find other polar coordinates \( (r, \theta) \) of the point for which the following are true. (a) \( r>0,-2 \pi \leq \theta<0 \) (b) \( r<0,0 \leq \theta<2 \pi \) (c) \( r>0,2 \pi \leq \theta<4 \pi \)

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INSTANT ANSWER

an inner radius of \( 11 \mathrm{~cm} \) and an outer radius of \( 29 \mathrm{~cm} \). Three forces (acting perpendicular to the axis of rotation) of magnitudes \( 11 \mathrm{~N} \), \( 23 \mathrm{~N} \), and \( 16 \mathrm{~N} \) act on the object, as shown. The force of magnitude \( 23 \mathrm{~N} \) acts \( 30^{\circ} \) below the horizontal. Find the magnitude of the net torque on the wheel about the axle through the center of the object. Answer in units of \( \mathrm{N} \cdot \mathrm{m} \).

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ANSWERED

Ralph Maestre verified

Numerade educator

A solid ball with a mass of 2.11 kg and a radius of 0.051 m starts from rest at the top of a 89.1° slope with a vertical height of 3.20 m. It proceeds to roll without slipping down the slope. What is the translational speed of the ball when it reaches the bottom? The acceleration of gravity is 9.81 m/s². Answer in units of m/s.

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INSTANT ANSWER

\( 00210.0 \) points A solid ball with a mass of \( 2.11 \mathrm{~kg} \) and a radius of \( 0.051 \mathrm{~m} \) starts from rest at the top of a \( 89.1^{\circ} \) slope with a vertical height of \( 3.20 \) \( \mathrm{m} \). It proceeds to roll without slipping down the slope. What is the translational speed of the ball when it reaches the bottom? The acceleration of gravity is \( 9.81 \mathrm{~m} / \mathrm{s}^{2} \). Answer in units of \( \mathrm{m} / \mathrm{s} \).

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INSTANT ANSWER

\( 00210.0 \) points A solid ball with a mass of \( 2.11 \mathrm{~kg} \) and a radius of \( 0.051 \mathrm{~m} \) starts from rest at the top of a \( 89.1^{\circ} \) slope with a vertical height of \( 3.20 \) \( \mathrm{m} \). It proceeds to roll without slipping down the slope. What is the translational speed of the ball when it reaches the bottom? The acceleration of gravity is \( 9.81 \mathrm{~m} / \mathrm{s}^{2} \). Answer in units of \( \mathrm{m} / \mathrm{s} \).

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ANSWERED

Mahendra Kumar verified

Numerade educator

A 2 kg ring is released from rest and rolls down a slope. When it is 4.0 m below its initial position, what is it's rotational kinetic energy? (hint: what fraction of the K of a ring is rotational instead of linear?)

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ANSWERED

Eduard Sanchez verified

Numerade educator

A window washer is standing on a scaffold supported by a vertical rope at each end. The scaffold weighs 197 N and is 3.60 m long. Assume the 712 N worker stands 1.17 m from one end of the scaffold. What is the force on the rope farther from the worker? Answer in units of N. Answer in units of N

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INSTANT ANSWER

\( \mathrm{AJ} \) and \( / \mathrm{J} \) are angle bisectors of \( \Delta \mathrm{GH} \). Find the distance from \( \mathrm{J} \)

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