A 2 kg ring is released from rest and rolls down a slope. When it is 4.0 m below its initial position, what is it's rotational kinetic energy? (hint: what fraction of the K of a ring is rotational instead of linear?)
Added by Tasnim H.
Step 1
Step 1: Calculate the final velocity of the ring using the equation \(v^2 = u^2 + 2as\), where \(u = 0\), \(a = g = 10 \, m/s^2\), and \(s = 4 \, m\). Show more…
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