A hoop ( radius =0.5m) with a mass of 2.0 kg is rolling without slipping along a horizontal surface with a speed of 4.5 m/s. What is the rotational Kinetic energy of the hoop after 3 sec, if the angular acceleration is 2 rad/s2? ( I (hoop) = mR2 )
Added by Abigail U.
Step 1
First, we need to find the angular velocity after 3 seconds. We can use the equation: ω_f = ω_i + αt where ω_f is the final angular velocity, ω_i is the initial angular velocity, α is the angular acceleration, and t is the time. Show more…
Show all steps
Your feedback will help us improve your experience
Madhur L and 56 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A hoop (I = MR2) of mass 2.0 kg and radius 0.50 m is rolling at a center-of-mass speed of 15 m/s. What is its total Kinetic Energy?
Kamalesh B.
'hoop of mass 2 kg, radius 0.5 m is rotating about its center with an angular speed of 3 rad/s force of ION is applied tangentially at the rim Determine the rotational kinetic energy oh the hoop. (b) What is instantaneous change rate of the kinetic energy?'
Kratika B.
2. A 40-kg cylinder pulley with a radius of 0.2 m rotates at a constant angular speed of 4 rad/s. What is the rotational kinetic energy of the pulley? The moment of inertia for cylinder is given as I=1/2 mr2.
Pranay S.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD