A 4.00 kg block rests on a 30 degree incline. If the coefficient of the static friction between the block and the incline is 0.700, what magnitude of horizontal force F must act on the block to start it moving up the incline?
Added by Ines T.
Step 1
This is given by the equation Fg = m*g, where m is the mass of the block and g is the acceleration due to gravity. So, Fg = 4.00 kg * 9.8 m/s^2 = 39.2 N. Show more…
Show all steps
Close
Your feedback will help us improve your experience
Narayan Hari and 61 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A 4.00-kg block rests on a 30.0 degree incline as shown in Fig. 5-5. If the coefficient of static friction between the block and the incline is 0.700, with what magnitude force must a horizontal force act on the block to start it moving up the incline?
Khoobchandra A.
A 4.00-kg block rests on a 30.0° incline as shown in the figure. If the coefficient of static friction between the block and the incline is 0.700, what magnitude horizontal force F must act on the block to start it moving up the incline? A) 51.1 N B) 76.4 N C) 34.0 N D) 54.7 N E) 84.0 N
Pritesh R.
A $3.0 \mathrm{kg}$ block is at rest on a horizontal floor. If you push horizontally on the $3.0 \mathrm{kg}$ block with a force of $12.0 \mathrm{N},$ it just starts to move. (a) What is the coefficient of static friction? (b) A 7.0 kg block is stacked on top of the $3.0 \mathrm{kg}$ block. What is the magnitude $F$ of the force, acting horizontally on the $3.0 \mathrm{kg}$ block as before, that is required to make the two blocks start to move together?
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD