00:02
Welcome to this numerate tutorial.
00:06
It is assumed that the motor at full load is maintaining its rpm at the rate load of 355 rpm.
00:18
So therefore, if we convert the 40 brake horsepower ac induction motor output to its mechanical wattage value, we get 29 ,000840 watts of mechanical power, the 1 ,000.
00:38
Watt standard loss is included in the 84 .2 percent electromotive efficiency at full load.
00:54
So therefore, if we multiply the available power output in mechanical wattage times the reciprocal .842, we can compute the input power watts in the form of ac.
01:16
Electrical true power.
01:18
So that's the input power connected to the motor.
01:24
The motor at full load.
01:26
Then incurs an 84 .2 % electro motive efficiency.
01:32
And then the conversion of electrical power to mechanical power yield to 29 ,840 watt output mechanical power.
01:44
There's 746 watts to 1.
01:48
Horsepower so 2980 2980 20840 watts mechanical power is equal to 40 brake horsepower so with that the wattage efficiency loss is a difference between the input power and electrical electricity from the mechanical power output and this equates to 5599 .4 watts so the brake horsepower formula is 2 pi times rpm times foot pounds torque divided into 33 ,000 foot pounds per minute...